Angelo invested $4,000into two accounts. One account paid 4%interest and the other paid 9%interest. He earned 6%interest on the total investment. How much money did he put in each account?

Answer:The amount invested in account that paid 4% was $2,400The amount invested in account that paid 9% was $1.600Step-by-step explanation:Letx -----> amount invested in account that paid 4%(4,000-x) -----> amount invested in account that paid 9%we know thatThe linear equation that represent this scenario is[tex]x(0.04)+(4,000-x)(0.09)=4,000(0.06)[/tex] Solve for x[tex]0.04x+360-0.09x=240[/tex] [tex]0.09x-0.04x=360-240[/tex] [tex]0.05x=120[/tex] [tex]x=\$2,400[/tex] [tex](4,000-x)=4,000-2,400=\$1,600[/tex] thereforeThe amount invested in account that paid 4% was $2,400The amount invested in account that paid 9% was $1.600