Write each quadratic function below in terms of linear factors.a)f(x)=x²-25b)f(x)=x²+25c)f(x)=4x²+25d)f(x)=x²-2x+1e)f(x)=x²-2x+4

Answer:a) (x + 5) (x - 5)b) (x + 5i) (x - 5i)c) (x + (5i/2)) (x - (5i/2))d) (x-1)(x-1)e) x +i√3 +1) (x -i√3+1)Step-by-step explanation:To solve this, we will need to factorize each quadratic function making it equal to zero first and then proceeding to find x  a) f(x) = x²-25x²-25 = 0⇒(x + 5) (x - 5)b) f(x)=x²+25x² + 25 = 0x²= -25x = √-25x = √25ix = ±5i⇒(x + 5i) (x - 5i)c) f(x)=4x²+254x²+25 = 04x²= -25x² = -25/4x = ±√(-25/4)x = ±(√25i)/2x = ±5i /2 ⇒(x + (5i/2)) (x - (5i/2))d) f(x)=x²-2x+1x²-2x+1 = 0⇒(x - 1)²e) f(x)=x²-2x+4x²-2x+4 = 0x²-2x = -4 x²-2x +1 = -4 +1x²-2x + 1 = -3(x-1)² +3 = 0(x-1)²= -3x-1 = √-3x = ±√3i +1⇒(x +i√3 +1) (x -i√3+1)